What is inoculum preparation in fermentation?

Inoculum preparation involves obtaining the organisms in an optimal state that is compatible with inoculation into cell culture, tissue culture, media, and fermentors. The prime objective is usually to achieve a high level of viable biomass in a suitable physiological state for use as an inoculum.

How much quantity of inoculum is usually used in fermentation?

Normally, one uses 5-10% v/v, which means what Dr. Belaouni detailed above. If you are setting a1L-culture you may add 50-100 mL of inoculum (or starter). Being strict, quantitatively, you should discount this volume from the total volume of culture (as Belaouni said).

What is inoculation in fermentation?

The fermentation process involves an inoculum development step, which is the preparation of a population of microorganisms from a stock dormant culture to a state useful for inoculating a final production fermenter.

What is inoculation method?

Inoculation is the study of introducing microorganisms into environments where they will grow and reproduce. In other words, we can say that inoculation means introducing a certain substance into another substance. For example, inoculation is adding a certain type of nutrient or chemical into a suspension of bacteria.

What is source of inoculum?

Mummified fruit was the main source of primary inoculum for species of Alternaria and Epicoccum, whereas mummified fruit and bark were equally important for species of Colletotrichum and Diaporthe.

What are the important factors that should be considered during the inoculum development?

During each stage of the inoculum development, aseptic conditions are maintained, and the pH, temperature, and carbon and nitrogen concentrations are controlled strictly. The fermentation is carried out over 72–96 h, and the viscosity and biomass are monitored constantly.

How do you calculate inoculum?

If you intent is to establish by inoculation 50 liters at 10^5/ml, think you’ll need 500 ml of 10^7/ml inoculum in those 50 liters (i.e. 500ml inoculum in 49.5 liters). Consider: concentration x volume = concentration x volume.