Why is the PV curve for an adiabatic process?
Why is the PV curve for an adiabatic process?
Answer. As γ is always greater than 1, the slope of an adiabatic curve is greater than that of an isothermal curve by a factor of γ. Hence the adiabatic curve is steeper than the isothermal curve, in both the processes of expansion and compression.
What is an adiabatic process and explain its thermodynamics?
adiabatic process, in thermodynamics, change occurring within a system as a result of transfer of energy to or from the system in the form of work only; i.e., no heat is transferred. A rapid expansion or contraction of a gas is very nearly adiabatic.
What is a real life example of adiabatic?
An example of an adiabatic process is the vertical flow of air in the atmosphere; air expands and cools as it rises, and contracts and grows warmer as it descends. Another example is when an interstellar gas cloud expands or contracts.
Where do adiabatic processes occur?
Any process that occurs within a container that is a good thermal insulator is also adiabatic. Adiabatic processes are characterized by an increase in entropy, or degree of disorder, if they are irreversible and by no change in entropy if they are reversible. Adiabatic processes cannot decrease entropy.
How do you find the adiabatic curve?
p1V1κ = p2V2κ in which κ = cp/cv is the ratio of the specific heats (or heat capacities) for the gas. One for constant pressure (cp) and one for constant volume (cv). Note that this ratio κ = cp/cv is a factor in determining the speed of sound in gas and other adiabatic processes.
How do adiabatic and isothermal curves differ?
| Difference Between Isothermal and Adiabatic process | |
|---|---|
| Isothermal | Adiabatic |
| Transfer of heat occurs | No Transfer of heat occurs |
| The pressure is more at a given volume | The pressure is less at a given volume |
| The temperature remains constant | The temperature changes due to internal system variations. |
How is adiabatic work calculated?
With the adiabatic condition of Equation 3.7. 1, we may write p as K/Vγ, where K=p1Vγ1=p2Vγ2. The work is therefore W=∫V2V1KVγdV=K1−γ(1Vγ−12−1Vγ−11)=11−γ(p2Vγ2Vγ−12−p1Vγ1Vγ−11)=11−γ(p2V2−p1V1)=11−1.40[(1.23×106N/m2)(40×10−6m3)−(1.00×105N/m2)(240×10−6m3)]=−63J.
